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 Date:-29 Jul 2010 00:24 AM
I.Vigneswar
Join Date: 15 Jun 2010
N=123456789123456789...180 DIGITS...WHEN N IS DIVIDED BY 37..WHAT WILL BE THE ANSWER...
I AM GETTING THE ANSWER AS 12..IS THAT RIGHT
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 Date:-29 Jul 2010 11:59 AM
Maheshwaran R
Join Date: 13 Mar 2010
No, it is 17.
Consider 123456789. For 37, we group in sets of 3 (as (10^3) % 37 = 1), & so (123+456+789) % 37 = 36 = -1.
20 such sets are there in the number in question, so 20 * (-1) = -20. So remainder is 37-20=17.

PS: I verified this with 'bc' (basic calculator in Linux which lets you deal with huge nos.)
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 Date:-29 Jul 2010 12:33 PM
I.Vigneswar
Join Date: 15 Jun 2010
I CONSULTED WITH BYJU..HE SAID 12 IS CORRECT
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 Date:-02 Aug 2010 19:35 PM
Maheshwaran R
Join Date: 13 Mar 2010
Like I said, I verified the answer on a computer. How did you arrive at 12?
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 Date:-07 Aug 2010 15:47 PM
jitesh Issrani
Join Date: 13 Mar 2010
Even I have verified. The answer is 17.

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